Earth mean radius
WebMass (10 24 kg) 5.9722 Volume (10 10 km 3) 108.321 Equatorial radius (km) 6378.137 Polar radius (km) 6356.752 Volumetric mean radius (km) 6371.000 Core radius (km) 3485 Ellipticity (Flattening) 0.003353 Mean … WebThe mean radius of Earth is at around 3.958 mi / 6.371 km, slightly larger than Venus, almost twice the radius of Mars and about three times that of Mercury. If you started walking from one end to the other, you would …
Earth mean radius
Did you know?
WebEarth radius. Since the Earth is flattened at the poles and bulges at the equator, geodesy represents Earth's shape with an oblate spheroid. The oblate spheroid, or oblate ellipsoid, is an ellipsoid of revolution … WebAfter a month, the Earth would have expanded by 26 kilometers—an increase of 0.4%—and its mass would have increased by 1.2%. Surface gravity would only have gone up by 0.4%, rather than 1.2%, since surface gravity is proportional to radius. [6]
WebA low Earth orbit (LEO) is an orbit around Earth with a period of 128 minutes or less (making at least 11.25 orbits per day) and an eccentricity less than 0.25. Most of the artificial objects in outer space are in LEO, with an altitude never more than about one-third of the radius of Earth.. The term LEO region is also used for the area of space below an … WebJust multiply the value in degrees by 111195 - this value is (Earth mean radius)*PI/180 - that is 'mean length of one great circle degree in meters on Earth's surface'. The result obtained using this method is within 1% of the geodesic …
WebBy how many newtons does the weight of a 100-kg person change when he goes from sea level to an altitude of 5.0 km if we neglect the earth's rotational effects? (The mean radius of the Earth is 6.38 × 106 m, G = 6.67 × 10-11 N ∙ m2/kg2.) A) -0.60 N WebExplanation:The only force acting on the satellite is the gravitational force from earthAccording to law of gravitation, Gravitational Force= Fg=Gm1m2 …. NASA launches a satellite into orbit at a height above the surface of the Earth equal to the Earth's mean radius. The mass of the satellite is 630 kg.
Web16 rows · R = earthRadius returns the scalar value 6,371,000, the mean radius of the Earth in meters. example R = earthRadius (lengthUnit) returns the mean radius of the Earth …
WebIt is the radius of a circle that fits the earth curvature in the North -South (the meridian) at the latitude chosen. The equations for the relation between the differential distances and angles are now: = φ λ = φ dE R cos d dN R d , N M The new radii of curvature are used in place of the simple single radius of the sphere. how does lizabeth change in marigoldsWebFeb 10, 2014 · Since the Earth is an oblate spheroid, closely approximated by an ellipsoid, the IUGG defines the Earth's mean radius using: a = Equatorial radius (6,378.1370 km) … how does llc distribute profitsWebNASA launches a satellite into orbit at a height above the surface of the Earth equal to the Earth's mean radius. The mass of the satellite is 840 kg. (Assume the Earth's mass is 5.97 1024 kg and its radius is 6.38 106 m.) NASA launches a satellite into orbit at a height above the surface of the Earth equal to the Earth's mean radius. how does liver regulate blood glucose levelsWebPhysics Question A 600-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth’s mean radius. Find the period of its revolution. Solution Verified Create an account to view solutions Recommended textbook solutions Physics for Scientists and Engineers: A Strategic Approach with Modern Physics how does liver disease cause hypoglycemiaWebStudy with Quizlet and memorize flashcards containing terms like A satellite of mass 500 kg orbits the earth with a period of 6,000 s. The earth has a mass of 5.97 × 10 24 kg, a radius of 6.38 × 10 6 m, and G = 6.67 × 10 -11 N ∙ m2/kg2. (a) Calculate the magnitude of the earth's gravitational force on the satellite. (b) Determine the altitude of the satellite above … how does livestock cause pollutionWebWe need the masses of the Moon and the Sun and their distances from Earth, as well as the radius of Earth. We use the astronomical data from Astronomical Data. Solution Substituting the mass of the Moon and mean distance from Earth to the Moon, we have F 12 =G m1m2 r2 =(6.67 × 10−11N⋅m2/kg2) (1.0kg)(7.35×1022kg) (3.84×108±6.37×106m)2. photo of chaz bono todayWebApr 3, 2024 · Polar radius (1 bar level) (km) 24,341: 3.829: Volumetric mean radius (km) 24,622: 3.865: Ellipticity (Flattening) 0.01708: 0.00335: 5.10: Mean density (kg/m 3) 1,638: 5,513: ... 4711.0 Apparent diameter from Earth Maximum (seconds of arc) 2.4 Minimum (seconds of arc) 2.2 Mean values at opposition from Earth Distance from Earth (10 6 … photo of chef way