WebQuestion: Find the remainder when (a) 32463 is divided by 8 (b) 7103 + 65409 is divided by 3. Find the remainder when (a) 32463 is divided by 8 (b) 7103 + 65409 is divided by 3. Expert Answer. Who are the experts? Experts are tested by Chegg as specialists in their subject area. We reviewed their content and use your feedback to keep the ... WebIf 7103 is divided by 25, then the remainder is (A) 20 (B) 16 (C) 18 (D) 15. Check Answer and Solution for above question from Mathematics in Binomial Tardigrade
If 7103 is divided by 25 then the remainder is - BYJU
WebThe remainder when 337 is divided by 80 is Byju's Answer Other Quantitative Aptitude Divisibility Rule for Powers of 2 & 5 The remainder... Question The remainder when 337 is divided by 80 is A 78 B 3 C 2 D 35 Solution The correct option is B 3 337 =34.9.3 =3.(81)9 =3(80+1)9 = 3(9C0 809+9C1.808+....+9C9) T hus, required remainder is equal to 3 WebOct 16, 2024 · Find the remainder when $13^{13}$ is divided by $25$.. Here is my attempt, which I think is too tedious: Since $13^{2} \equiv 19 (\text{mod} \ 25),$ we have $13^{4} \equiv 19^{2} \equiv 11 (\text{mod} \ 25)$ and $13^{8} \equiv 121 \equiv 21 (\text{mod} \ 25).$ Finally, we have $13^{8+4} \equiv 13^{12} \equiv 21\times 11 \equiv … thermon.com
The remainder when 337 is divided by 80 is - BYJU
WebMay 20, 2024 · Hence, when 7103 is divided by 25, it leaves a remainder 18. Advertisement New questions in Math le 1: Multiply 33 x 15. If x=2+√3 and xy= 1 then x/√2+ √x+y/√2-√√y Divide 20 chocolates between sonu and monu in the ratio of 3:2 . Prove the following Identities: Q.1 1-2 Sin² 0-2 Cos² 0-1 Q.2 Cos 0 Sin¹01-2 Sin²0 WebThat is, when you divide any polynomial by the linear divisor "x − a", your remainder will, and must, be just some plain number. The Remainder Theorem thus points out the connection between division and multiplication. For instance, since 12 ÷ 3 = 4, then 4 × 3 = 12. If your division ends with a non-zero remainder left over, then, when you ... WebOct 25, 2024 · D. 7. E. 1. 333 222 = ( 329 + 4) 222 = ( 7 ∗ 47 + 4) 222. Now if we expand this, all terms but the last one will have 7*47 as a multiple and thus will be divisible by 7. The last term will be 4 222 = 2 444. So we should find the remainder when 2 444 is divided by 7. 2^1 divided by 7 yields remainder of 2; thermon colorado